Collatz Conjecture
Night_Watch
Member Posts: 514
in Off-Topic
I thought it would be interesting if everyone interested took turns doing the Conjecture in sequential order for fun (you can do as many as you'd like but please keep them in order.) If you don't know what the Collatz Conjecture is then http://en.wikipedia.org/wiki/Collatz_conjecture Basically if the number is even you divide by 2 and if it's odd you multiply by 3 and add 1. you keep doing that with whatever number you get and eventually you get to 1. Please feel free to participate but no cheating (i.e. searching the internet for lists of number solutions.) Go ahead and use a calculator, it's gets a little ridonculous with some of the higher numbers (I think 27 has over a 100 numbers you have to go through before you get to 1 and some of them go in to the thousands) I'll start the first 10 since they're easy and to give folks a general idea
Remember. if even then divide by 2, if odd then 3x+1
1 =P
2, 1 XD
3, 10, 5, 16, 8, 4, 2, 1
4, 2, 1
5, 16, 8, 4, 2, 1
6, 3, 10, 5, 16, 8, 4, 2, 1
7, 22, 11, 34, 17, 52, 26, 13, 40, 20, 10, 5, 16, 8, 4, 2, 1
8, 4, 2, 1,
9, 28, 14, 7, 22, 11, 34, 17, 52, 26, 13, 40, 20, 10, 5, 16, 8, 4, 2, 1
10, 5, 16, 8, 4, 2, 1
thank you xkcd
Remember. if even then divide by 2, if odd then 3x+1
1 =P
2, 1 XD
3, 10, 5, 16, 8, 4, 2, 1
4, 2, 1
5, 16, 8, 4, 2, 1
6, 3, 10, 5, 16, 8, 4, 2, 1
7, 22, 11, 34, 17, 52, 26, 13, 40, 20, 10, 5, 16, 8, 4, 2, 1
8, 4, 2, 1,
9, 28, 14, 7, 22, 11, 34, 17, 52, 26, 13, 40, 20, 10, 5, 16, 8, 4, 2, 1
10, 5, 16, 8, 4, 2, 1
thank you xkcd
1